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    Find which part of city get least amount of rainfall.


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    During a rain storm different parts A,B, and C of a city received different amounts of rainfall. if A received 18/5 cm, B received 29/8 cm and C received 25/7cm of rainfall, which part of the city received the least amount of rainfall. This is one of the word problem in mathematics. Can you provide the answer for the above specified word problem?
    Experts: do assist.
  • #139301
    Given that part A get 18/5 cm of rainfall, B get 29/8 cm of rainfall and C get 25/7 cm of rainfall.
    LCD of denominator 5,8 and 7 is 280. Then the equivalent amount of rainfall with LAM 280 as denominator are
    18/5=(18/5) x (56/56)=1008/280
    29/8=(29/8) x (35/35)= 1015/280
    25/7=(25/7) x (40/40)= 1000/280
    That means, 1008, 1015 and 1000 for part A,B and C respectively.
    Therefore, part C of the city received the least amount of rainfall, which is 1000/280 cm.

  • #139350
    since there is no confusion in the question
    part A gets 18/5=3.60 cm rainfall
    part B gets 29/8=3.625 cm rainfall
    part C gets 25/7=3.571 cm rainfall

    so part C gets the least rainfall.

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  • #139382
    Hi,
    Part A of city receives rainfall = 18/5,
    Part B of city receives rainfall = 29/8 and
    Part C of city receives rainfall = 25/7
    for equalising the denominator of each fraction we multiply it as,

    18/5 x56/56, 29/8 x35/35, 25/7x 40/40

    = 1008/280, 1015/280, 1000/280
    Now it is clear that part C of the city gets least rainfall.

  • #139644
    Part A gets 18/5=3.60 cm rainfall
    Part B gets 29/8=3.625 cm rainfall
    Part C gets 25/7=3.571 cm rainfall

    so part C gets the least rainfall.


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