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Forums » Education » General »
Posted Date: 05 Jun 2009 Posted By:: Malathi Member Level: Silver Member Rank: 3948 Points: 1
Responses:
3
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main()
{
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++) {
printf(" %d ",*c);
++q; }
for(j=0;j<5;j++){
printf(" %d ",*p);
++p; }
}
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Responses
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#88903 Author:  Deepakkumar Devarajan Member Level: Gold Member Rank: 0 Date: 05/Jun/2009 Rating:  Points: 2 |
Hi Malathi,
It might cause an error , as variable c is not a pointer . i am not sure about it . Please join my community and post the same
http://www.indiastudychannel.com/sites/152280/-Tech-World.aspx
Regards,
Deepakkumar D
Join My community :
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| #88929 Author: Gopal Bhageria Member Level: Bronze Member Rank: 0 Date: 05/Jun/2009 Rating: Points: 3 |
Does not give an error. The answer to this is:- 2222228344
*) c in itself is a pointer to the first element of an array.
*) the first loop prints *c without incrementing c itself, hence only 2 gets printed for each iteration
*) for the second loop, as p is incremented as well, it gets incremented by one array position and hence, the array is iterated.
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