Determination of fluoride by SPADNS method


Posted Date:     Total Responses: 0    Posted By: Prabha Kishore   Member Level: Gold   Points/Cash: 2   


Procedure:

1.Preparation of the reagent: 958 mg of SPADNS is dissolved in distilled water and diluted to 500 ml. 133 mg of zirconyl chloride octahydrate (ZrCl2.8H2O) is dissolved in 25 ml distilled water and 350 ml of conc.HCl is added and diluted to 500 ml with distilled water. Equal volumes of SPADNS solution and zirconyl acid solutions are mixed.

2.Preparation of calibration curve: 0.221 g of anhydrous sodium fluoride is dissolved in water and diluted upto one liter. The stock solution is further diluted to get standard solution having 10 mg per liter of fluoride.

3.1,2,3,4,5 and 6 ml’s of this solution is pipetted out into 50 ml standard flasks. 10 ml of zirconyl-SPADNS reagent and one drop of NaAsO2 (to remove residual chlorine) are added to each of the solutions. It is diluted up to the mark and mixed well. The absorbance of the solutions are measured at 570 nm against a reagent blank and a calibration plot is constructed by plotting absorbance against concentrations using colorimeter.
4.Suitable aliquot of water sample is taken and repeated the step 3
5.Using the calibration curve, the concentration of F-/L is calculated.


Project Feedbacks

Author: Member Level: BronzeRevenue Score: 2 out of 52 out of 5
Thank for your method that you uploaded. But I think you should post the method more detail for other members understanding deeply.


Author: Member Level: BronzeRevenue Score: 2 out of 52 out of 5
please send detail method for fluoride by spands method in waste water. calibration of fluoride should be give in details .


Author: Member Level: BronzeRevenue Score: 2 out of 52 out of 5
u did good by uploading this method but for a comon person its not possible to easily under stand it. So plz give detail that how spadns react and what happens to floride or floride sample.thanx


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