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Posted By: S.Yamininagarajan Member Level: Diamond Posted Date: 10 Jul 2008 Category: Aptitude Test

Given the following functions
(1) f(n a b c ) = ac if n=1
(2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1
Then what is the value f( 2 a b c ) = ?

Select Answer:

f( 2 a c b ) = ab + ac + bc.
f( 2 a c b ) = ab + bc + bc.
f( 2 a c b ) = ab + ac + cb.
None of the above

Your Test Score: 0 / 0

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Previous Question: Diamond’s value is proportional to its weight2 .When the diamond broke wts of pieces in ratio 1:2:3;4:5. Total loss in value is 85,000.What is the value of the diamond twice the wt of the original diamond.

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Given the following functions (1) f(n a b c ) = ac if n=1 (2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1 Then what is the value f( 2 a b c ) = ?

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Given the following functions
(1) f(n a b c ) = ac if n=1
(2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1
Then what is the value f( 2 a b c ) = ?