My Profile
Active Members
TodayLast 7 Days
more...
Awards & Gifts
Online Exams
Fresher Jobs
Our fresher job section is exclusively for fresh graduates! Find jobs for freshers in major Indian
cities including Bangalore, Chennai, Hyderabad, Pune or Kochi
Resources
Find educational articles, blogs, discussion threads and other resources.
Colleges
Find details about any college in India or search for courses.
|
How to solve Linear Equations
Posted Date: 18 Mar 2008 Resource Type: Articles/Knowledge Sharing Category: General
|
Posted By: mark richards Member Level: Silver
Rating:  Points: 4
|
|
|
Today’s topic deals with how to solve linear and quadratic equations. Before we begin this topic, I will first teach you how to identify a linear and a quadratic equation. A linear equation comes in the form, ax + b = c ……where a, b & c are any value. The main idea of identifying a linear equation is that, the highest power of x existing in the equation must be 1. A quadratic equation comes in the form ax^2 +bx + c = d ……where a, b, c & d are any value. The main idea of identifying a quadratic equation is that, the highest power of x existing in the equation must be 2.
Now let’s learn how to solve linear equations. This is easy when compared to solving quadratic or even cubic equations. Luckily for you, the S.A.T doesn’t give you any cubic equations to solve, but the quadratic equations are popular.
1) 2x +3 = 9……..what is x?
That question is simple. All you have to do is carry all the numbers on one side and keep x on the other side. So it look like
2x = 9 – 3 …….2x = 6………x = 3
but the questions in the S.A.T have a little addition.
1) 2x +3 = 9……..what is 4x – 3 ?.......you can solve for x like above and then substitute it into 4x – 3 to get 9, but why solve for x? They asked for 4x – 3. Let me show you my technique. As the above, when you got 2x = 6, multiply both sides by 2 so that you get, 4x =12….. and then minus 3 and you get 9. As I told you before a large percentage of the Math in the S.A.T doesn’t require you to solve for x. You have to manipulate the question for you to gain time in the exam. Linear equations appear in the first 5 questions of the exam.
2) 6 + 5(2x + 3) = 31…..another linear equation.
First you must expand the brackets and then solve it just like above……6 + 10x + 15 = 31
10x = 31 – 15 – 6
10x = 10
x = 1
That’s about it for linear equations.
For more details, visit http://mathssat.blogspot.com/
|
Responses
|
No responses found. Be the first to respond and make money from revenue sharing program.
|
|
Watch TV Channels
|