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Program no. 3 (probability)
#include
#include
#include
void main()
{
textcolor(GREEN);
clrscr();
float a1,a2,b1,b2,c1,c2;float p1,p2;
cout<<"enter the odds for 1st critic in the form (x y) : ";
cin>>a1>>a2;
cout<<"enter the odds for 2nd critic in the form (x y) : ";
cin>>b1>>b2;
cout<<"enter the odds for 3rd critic in the form (x y) : ";
cin>>c1>>c2;
cout<<"\ncase 1: when all three review the book ";
p1=((a1/(a1+a2))*(b1/(b1+b2))*(c1/(c1+c2)));
cout<<"\n\aa\nthe probability in this case is "<cout<<"\n\n\acase 2: when any two review the book ";
p2=((a1/(a1+a2))*(b1/(b1+b2))*(c2/(c1+c2)))+((a2/(a1+a2))*(b1/(b1+b2))*(c1/(c1+c2)))+((a1/(a1+a2))*(b2/(b1+b2))*(c1/(c1+c2)));
cout<<"\nthe probability in this case is "<cout<<"\n\a\nbut required probability is sum of two probabilities that
is "<delay(100);
textcolor(RED);
cout<<"\n\n\a";
cprintf("PROGRAM DESIGNED BY:ASHISH KUMAR");
cout<<"\n\n";
cprintf("/ roll 249/06 ");
getch();
}
output:
enter the odds for 1st critic in the form (x y) : 5 2
enter the odds for 2nd critic in the form (x y) : 4 3
enter the odds for 3rd critic in the form (x y) : 3 4
case 1: when all three review the book
the probability in this case is 0.174927
case 2: when any two review the book
the probability in this case is 0.434402
but required probability is sum of two probabilities that is 0.609329
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