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C++ Program for probability- 4
Posted Date: 23 Mar 2008 Resource Type: Articles/Knowledge Sharing Category: Computer & Technology
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Posted By: ashish singh Member Level: Diamond
Rating:  Points: 3
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//Program no. 4 (probability)
#include
#include
#include
void main()
{
textcolor(GREEN);
clrscr();
float a1,a2,b1,b2,c1,c2,p1,p2;
cout<<"enter the success ratio of A in the form (x,y) : ";
cin>>a1>>a2;
cout<<"enter the success ratio of B in the form (x,y) : ";
cin>>b1>>b2;
cout<<"enter the success ratio of C in the form (x,y) : ";
cin>>c1>>c2;
cout<<"\n\awhen any two hit the shot ";
p1=((a1/a2)*(b1/b2)*((c2-c1)/(c2)))+(((a2-a1)/a2)*(b1/b2)*(c1/(c2)))+((a1/a2)*((b2-b1)/b2)*(c1/c2));
cout<<"\n\nthe probability in this case is "<cout<<"\nwhen all three review the book ";
p2=((a1/a2)*(b1/b2)*(c1/c2));
cout<<"\n\nthe probability in this case is "<cout<<"\nthe required probability is "<delay(100);
textcolor(RED);
cout<<"\n\n\a";
cprintf("PROGRAM DESIGNED BY:ASHISH KUMAR");
cout<<"\n\n";
cprintf("/ roll 249/06 ");
getch();
}
output:
enter the success ratio of A in the form (x,y) : 4 5
enter the success ratio of B in the form (x,y) : 3 4
enter the success ratio of C in the form (x,y) : 2 3
when any two hit the shot
the probability in this case is 0.433333
when all three review the book
the probability in this case is 0.4
the required probability is 0.833333
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