Q1.A person has n number of sons and n square number of cows.Each cow gives milk as per their serial number. For example cow number 1 gives 1 liter milk, cow number 2 gives 2 liter of milk and so on.Write a program in bluej(java) to solve the above problem
Solution 1:-
class cows
{
public void abc(int n)
{
int cows=n*n;
int a[][]=new int [n][n];
for(int i=0;i{
a[i][i]=i+1;
}
int d=n;
for(int j=0;j{
for(int k=0;k{
if(j!=k)
{
a[k][j]=d+1;
d=d+1;
}
}
}
for(int p=0;p{
int w=p+1;
System.out.print(w+"number son will get cows with serial numbers------");
for(int q=0;q{
System.out.print(a[p][q]+",");
}
System.out.println(" ");
}
}
}
** Input number of sons:-5
** Output number of cows:-1number son will get cows with serial numbers------1,10,14,18,22,
2number son will get cows with serial numbers------6,2,15,19,23,
3number son will get cows with serial numbers------7,11,3,20,24,
4number son will get cows with serial numbers------8,12,16,4,25,
5number son will get cows with serial numbers------9,13,17,21,5,
Q2.Program to find out the co prime numbers- written in Bluej(java)
Solution 2:
class AP
{int s;
public void abc(int a,int b,int n)
{
if(a>b)
{
for(int i=1;i<=b;i++)
{
if(a%i==0)
{
s=s+1;
}
}
if(s==0)
{
System.out.println("The numbers are coprime");
for(int j=0;j{int k=a+j*b;
System.out.print(k);
}
}
}
else
{
for(int i=1;i<=a;i++)
{
if(b%i==0)
{
s=s+1;
}
}
if(s==0)
{
System.out.println("The numbers are coprime");
for(int j=0;j{
int k=b+j*a;
System.out.print(k);
}
}
}
}
}
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