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Debug C code
Posted Date: 16 May 2008 Resource Type: Articles/Knowledge Sharing Category: Placement Papers
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Posted By: Shanthi M Member Level: Diamond
Rating:  Points: 1
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C code to Debug
1. int i=10;
printf("i=%d",i);
Can you think of any other way to print the value of i ?
Answer :
int i=10;
printf("i=%d",*(&i));
Explanation:
*(&i)means the value contained in the address location denoted by i.
2. #include "stdio.h"
main()
{
printf("%d %d",sizeof(NULL),sizeof(""));
}
Answer: 2 1
Explanation:
Because 'NULL' is defined to be 0 in stdio.h,the size of 0 which is an integer is 2 bytes. Even though the string has no characters, it has a null character '\0'. The size of this character is 1 byte.Hence the output is 2 1.
3. main()
{
int a=10;
int *p;
p=&a;
printf("a=%d",a);
printf("*p=%d",*p);
printf("&a=%d",&a);
printf("p=%u",p);
printf("value at p=%d",*(&a));
}
Note: The address of a is 1000.
Answer:
a=10
*p=10
&a=1000
p=1000
value at p=10
4.float a=4;
int i=2;
printf("%f %d",i/a,i/a);
printf("%d %f",i/a,i/a);
Output:
0.5 0
0 0
Explanation:
Conversion of lower byte to higher byte is not possible in printf statement. That is, %d is not converted to %f.
5. int x=10,y=5,p,q;
p=x>9;
q=x<3&&y!=3;
printf("%d %d",p,q);
Output: 1 1
6. int x=10,y=-20;
x=!x;
y=!y;
printf("%d %d",x,y);
Output: 0 0
Explanation:
Any value other than 0 following this logical NOT (!) is assumed to be 1.
7. int c=5,d=5,e=-10,a;
a=c>1?[d>1||e>1 ? 100:200]:300;
What is the value of a?
Output: 100
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Responses
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| Author: Vidya 23 May 2008 | Member Level: Diamond Points : 2 | useful information
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