My Profile
Active Members
TodayLast 7 Days
more...
Awards & Gifts
Online Exams
Fresher Jobs
Our fresher job section is exclusively for fresh graduates! Find jobs for freshers in major Indian
cities including Bangalore, Chennai, Hyderabad, Pune or Kochi
Resources
Find educational articles, blogs, discussion threads and other resources.
Colleges
Find details about any college in India or search for courses.
Advertisements
|
Do you know printf if yes then check this
Posted Date: 28 May 2008 Resource Type: Articles/Knowledge Sharing Category: Computer & Technology
|
Posted By: Avdhut Sonpethkar Member Level: Gold
Rating:  Points: 1
|
|
|
[Q001]. What will be the output of the following program :
void main()
{
printf();
}
(a)Run-Time Error (b)Compile-Time Error (c)No Output (d)None of these
Ans. (b) Since there must be enough arguments for the format.
_________________________________________________________________________________________________
[Q002]. What will be the output of the following program :
void main()
{
printf(NULL);
}
(a)Run-Time Error (b)Compile-Time Error (c)No Output (d)None of these
Ans. (c) Since NULL is a constant value or NULL pointer value or a NULL string.
_________________________________________________________________________________________________
[Q003]. What will be the output of the following program :
void main()
{
printf("%%",7);
}
(a)7 (b)Compile-Time Error (c)% (d)%%
Ans. (c) Since % is a format specifier & excess arguments (more than required by the format) are
merely ignored.
_________________________________________________________________________________________________
[Q004]. What will be the output of the following program :
void main()
{
printf("//",5);
}
(a)5 (b)Compile-Time Error (c)/ (d)//
Ans. (d) Since / is an escape sequence character & excess arguments (more than required by the format) are merely ignored.
_________________________________________________________________________________________________
[Q005]. What will be the output of the following program :
void main()
{
printf("d%",8);
}
(a)8 (b)Compile-Time Error (c)d% (d)None of these
Ans. (c) Since excess arguments (more than required by the format) are merely ignored.
_________________________________________________________________________________________________
[Q006]. What will be the output of the following program :
void main()
{
printf("%d"+0,123);
}
(a)123 (b)Compile-Time Error (c)No Output (d)None of these
Ans. (a) "%d"+0 has no effect on the output operation.
_________________________________________________________________________________________________
[Q007]. What will be the output of the following program :
void main()
{
printf("%d"+1,123);
}
(a)123 (b)Compile-Time Error (c)d (d)No Output
Ans. (c) "%d"+1 (i.e 1 or > 0) affects the program output by considering "%d" as string and ignores 123
Where 1 refers to the index i.e. 2nd character in the array or string "%d".
_________________________________________________________________________________________________
[Q008]. What will be the output of the following program :
void main()
{
printf("%d",printf("Hi!")+printf("Bye"));
}
(a)ByeHi!6 (b)Hi!Bye6 (c)Compile-Time Error (d)None of these
Ans. (b) Since L->R priority & the length of the strings 'Hi!' & 'Bye' is 3+3=6
_________________________________________________________________________________________________
[Q009]. What will be the output of the following program :
void main()
{
printf("%d",printf("Hi!")*printf("Bye"));
}
(a)ByeHi!6 (b)Hi!Bye9 (c)Hi!Bye (d)None of these
Ans. (b) Since L->R priority & the length of the strings 'Hi!' & 'Bye' is 3*3=9
_________________________________________________________________________________________________
[Q010]. What will be the output of the following program :
void main()
{
printf("%d",printf("")+printf(""));
}
(a)0 (b)No Output (c)Compile-Time Error (d)None of these
Ans. (a) Since L->R priority & the length of the 2 empty strings are : 0+0=0
_________________________________________________________________________________________________
[Q011]. What will be the output of the following program :
void main()
{
printf("Hi Friends"+3);
}
(a)Hi Friends (b)Friends (c)Hi Friends3 (d)None of these
Ans. (b) Since (base adress)+0 points to the value 'H'. Now the NEW (base address) equals
(base address)+3 that points to the character 'F'. Thus it prints the string from 'F' onwards.
_________________________________________________________________________________________________
[Q012]. What will be the output of the following program :
void main()
{
printf("C For ") + printf("Swimmers");
}
(a)Compile-Time Error (b)C For Swimmers (c)Run-Time Error (d)None of these
Ans. (b) It is a VALID C statement. Change the operators but the output remains same(NO EFFECT).
_________________________________________________________________________________________________
[Q013]. What will be the output of the following program :
void main()
{
printf("\/\*\-*\/");
}
(a)Run-Time Error (b)\/*-*\/ (c)/*-*/ (d)None of these
Ans. (c) Since \ is an escape sequence character. Be careful while analyzing such statements.
_________________________________________________________________________________________________
[Q014]. What will be the output of the following program :
int main()
{
int main=7;
{
printf("%d",main);
return main;
}
printf("Bye");
}
(a)Compile-Time Error (b)Run-Time Error (c)7Bye (d)7
Ans. (d) It is a VALID C statement. Prints 7 and returns the same to the OS. NOTE: Last printf
statement will not be executed.
_________________________________________________________________________________________________
[Q015]. What will be the output of the following program :
void main()
{
main();
}
(a)Compile-Time Error (b)Run-Time Error (c)Infinite Loop (d)None of these
Ans. (c) It is a VALID C statement. It is like a recursive function & the statements get executed
infinite number of times.
_________________________________________________________________________________________________
[Q016]. What will be the output of the following program :
void main()
{
printf("Work" "Hard");
}
(a)Work (b)Hard (c)No Output (d)WorkHard
Ans. (d) Since L->R priority. First it prints the word 'Work' & then 'Hard'.
_________________________________________________________________________________________________
[Q017]. What will be the output of the following program :
void main()
{
char str[]="%d";
int val=25;
printf(str,val);
}
(a)Compile-Time Error (b)Run-Time Error (c)25 (d)None of these
Ans. (c) It is a VALID C statement. First parameter contains the format specifier & the Second
parameter contains the actual value 25.
_________________________________________________________________________________________________
[Q018]. What will be the output of the following program :
void main()
{
int val=75;
printf("%d",val,.,.);
}
(a)Compile-Time Error (b)Unpredictable (c)75 (d)None of these
Ans. (b) Output is Unpredictable B'coz there are not enough arguments for the format. But it is a
VALID C statement.
_________________________________________________________________________________________________
[Q019]. What will be the output of the following program :
void main()
{
int val=10;
printf("%d",val+1,"%d",val--);
}
(a)10 (b)11 10 (c)11 9 (d)10 9
Ans. (a) Since R->L priority. The second format specifier '%d' is an excess argument and it is
ignored.
_________________________________________________________________________________________________
[Q020]. What will be the output of the following program :
void main()
{
int val=5;
printf("%d %d %d %d",val,--val,++val,val--);
}
(a)3 4 6 5 (b)5 5 6 5 (c)4 4 5 5 (d)None of these
Ans. (c) Since R->L priority.
_________________________________________________________________________________________________
[Q021]. What will be the output of the following program :
void main()
{
int val=5,num;
printf("%d",scanf("%d %d",&val,&num));
}
[NOTE : ASSUME 2 values are entered by the user are stored in the variables 'val' & 'num' respectively.]
(a)1 (b)2 (c)5 (d)None of these
Ans. (b) Since scanf statement returns the number of input fields successfully scanned, converted
& stored.
_________________________________________________________________________________________________
[Q022]. What will be the output of the following program :
#define Compute(x,y,z) (x+y-z)
void main()
{
int x=2,y=3,z=4;
printf("%d",Compute(y,z,(-x+y)) * Compute(z,x,(-y+z)));
}
(a)40 (b)30 (c)Compile-Time Error (d)None of these
Ans. (b) Since it is macro function. NOTE : Be careful while doing such type of calculations.
_________________________________________________________________________________________________
[Q023]. What will be the output of the following program :
void main()
{
int m=10,n=20;
printf("%d %d %d",m/* m-value */,/* n-value */n,m*/* Compute m*n */n);
}
(a)Run-Time Error (b)10 20 200 (c)Compile-Time Error (d)None of these
Ans. (b) Since comments /*...*/ are ignored by the compiler.
_________________________________________________________________________________________________
[Q024]. What will be the output of the following program :
void main()
{
int m=10,n=20;
/* printf("%d",m*n);
}
(a)VALID but No Output (b)VALID : Prints 200 (c)Compile-Time Error (d)None of these
Ans. (c) Since COMMENT statement not ended properly i.e */ is missing in the above program.
_________________________________________________________________________________________________
[Q025]. What will be the output of the following program :
void main()
{
int val=97;
"Printing..."+printf("%c",val);
}
(a)Printing...97 (b)97 (c)Compile-Time Error (d)a
Ans. (d) Since alphabet 'a' is the ASCII equivalent of 97.
_________________________________________________________________________________________________
[Q026]. What will be the output of the following program :
void main()
{
int val=5;
val=printf("C") + printf("Skills");
printf("%d",val);
}
(a)Skills5 (b)C1 (c)Compile-Time Error (d)CSkills7
Ans. (d) VALID Since 'printf' function return the no. of bytes output.
_________________________________________________________________________________________________
[Q027]. What will be the output of the following program :
void main()
{
char str[]="Test";
if ((printf("%s",str)) == 4)
printf("Success");
else
printf("Failure");
}
(a)TestFailure (b)TestSuccess (c)Compile-Time Error (d)Test
Ans. (b) VALID Since 'printf' function return the no. of bytes output.
_________________________________________________________________________________________________
[Q028]. What will be the output of the following program :
void main()
{
int val=5;
printf("%*d",val);
}
(a) 5 (b)5 (c)Compile-Time Error (d)None of these
Ans. (a) VALID Since '*' specifies the precision (i.e. the next argument in the precision). If no
precision is specified then the value itself will be the precision value. Thus it prints 5 BLANK
SPACES & then the value 5.
_________________________________________________________________________________________________
[Q029]. What will be the output of the following program :
void main()
{
int val=5;
printf("%d5",val);
}
(a)Compile-Time Error (b)5 (c)55 (d) 5
Ans. (c)
_________________________________________________________________________________________________
[Q030]. What will be the output of the following program :
void main()
}
int val=5;
printf("%d",5+val++);
{
(a)Compile-Time Error (b)5 (c)10 (d)11
Ans. (a) Since incorrect usage of pair of braces } and {. Correct usage : Each compound statement
should be enclosed within a pair of braces, i.e { and }.
|
Responses
|
| Author: Shanthi M 28 May 2008 | Member Level: Diamond Points : 2 | Its very interesting and useful.
Thank you
|
|
|