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Java Program-Sort contents file

Posted Date: 18 Jun 2008 Resource Type: Articles/Knowledge Sharing Category: Computer & Technology

Posted By: Girish Patil Member Level: Diamond
Rating:

Points: 3

import java.io.*;

public class sortfile
{
public static void main(String args[]) throws Exception
{
RandomAccessFile a;
a=new RandomAccessFile("a.txt","r");
int count=0;
String b;
while((b=a.readLine())!=null)
{
count++;
}

String[] p;
p=new String [count];
int i,j;
i=0;
a.seek(0);

while((b=a.readLine())!=null)
{
p[i]=b;
i++;
}

String temp;

for(i=0;i<=count-2;i++)
{
for(j=i+1;i<=count-1;j++)
{
if(p[j].compareTo(p[i])<0)
{
temp=p[i];
p[i]=p[j];
p[j]=temp;
}
}
}

PrintStream c;
c=new PrintStream("sorted.txt");
for(i=0;i {
c.println(p[i]);
}

a.close();
c.close();
}
}

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