# Classroom lecture about basics of Maths algebra.

I know Maths is a subject where we need understand the basic, without learning basic we can learn it. Today I will teach you about how to solve an equationExample 1 :

Let's say we have an equation 4x-3=5

Step 1 take constant 3 to the other side then negative sign of 3 will change as its the rule the sign changes form + to - and vice versa when we take any constant or variable to the other side. So the equation now becomes 4x=3+5=8

Step 2 Now when we take 4 to the other side it becomes denominator and equation becomes x=8/4

And the answer comes out as x=2

Example 2 when we have two equations and have two variable x and y and have to find value of both.

3x+y=5-------1

x-4y=2--------2

In this case we will use substitution method.

Equation 1 can be written as

y=5-3x

Now we have value of y which can be substituted in 2 equation so equation 2 becomes

x-4(5-3x)=2

Now solving this equation it becomes

x-20+12x=2

Taking variable to one side and constants to another side it becomea

x+12x=2+20

So 13x= 22

x=22/13

Putting value of x in 1 or 2 equation we will get the value of y so putting it 2 equation, it becomes

22/13-4y=2

It now becomes

4y=22/13-2

4y= - 4/13

Hence y=( - 4/13)/4

y= - 1/13

Hence x=22/13 & y=-1/13

We can verify the answer by putting these values in any of the equation 1 or 2

If we put values in eq 1

It is 3*22/13+(-1/13) answer should be 5

After solving it we get 66/13-1/13=65/13=5

Hence above are the values of x and y

Hope you all understood how to solve the linear equations in next lecture I will teach about how to solve non linear equations.